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Question: Kepler's second law is a consequence of (A) Conservation of energy (B) Conservation of linear mo...

Kepler's second law is a consequence of
(A) Conservation of energy
(B) Conservation of linear momentum
(C) Conservation of angular momentum
(D) Conservation of mass

Explanation

Solution

Kepler's second law states that the planet moves in an elliptical orbit such that the line between it and the Sun placed at a focus sweeps out equal areas in equal times. Conservation of angular momentum states that the angular momentum of a body remains constant unless an external torque is applied.
Formula used:
The area of the triangle/wedge is A=12×base×heightA=\dfrac{1}{2} \times base \times height
rdθdt=vr\dfrac{{d\theta }}{{dt}} = v (Where vv is linear velocity, dθd\theta is an elemental angle which we have considered, rr is the radius of the orbit of which the wedge is a part anddtdtis the elemental time in which our observation is made.)
L=m(r×v)L = m(r \times v)(Where LL is angular momentum)

Complete step-by-step answer:

Consider a small wedge of the orbit traced out in time dtdt, dθd\theta is an elemental angle which we have considered, rr is the radius of the orbit of which the wedge is a part
So,
Area of the wedge is, A=12×base×heightA=\dfrac{1}{2} \times base \times height
The base is rr and height is rdθrd\theta , dAdA is the area of the wedge,
dA=12r×rdθ\Rightarrow dA = \dfrac{1}{2}r \times rd\theta
The rate at which area is swept out is,
dAdt=12r×rdθdt\Rightarrow \dfrac{{dA}}{{dt}} = \dfrac{1}{2}r \times r\dfrac{{d\theta }}{{dt}}
since rdθdt=vr\dfrac{{d\theta }}{{dt}} = v , where vv is linear velocity, θ\theta is the angle between rr and vv
dAdt=12rvθ\Rightarrow \dfrac{{dA}}{{dt}} = \dfrac{1}{2}rv\theta
We know that,
LL Is angular momentum and m is the mass of the object
L=m(r×v)\Rightarrow L = m(r \times v)
L=mrvsinθ\Rightarrow L = mrv \sin \theta

As θ\theta is very small, sinθθ\sin \theta \simeq \theta
L=mrvθ\Rightarrow L = mrv\theta
From the above equation, we can draw that,
dAdt=12Lm\Rightarrow \dfrac{{dA}}{{dt}} = \dfrac{1}{2}\dfrac{L}{m}
Hence dAdt\dfrac{{dA}}{{dt}} is constant with time as LL is constant (from conservation of angular momentum) and mass is also constant. This is what Kepler stated in his second law.

Hence option (C) Conservation of angular momentum is the correct answer.

Note
Kepler gave three such laws on the planetary motion we just saw and proved the second law given by Kepler. The first law explained that the earth moves in an elliptical orbit and the sun is present at one of the foci of that ellipse. The third law gave the relation between the length of the semi-major axis of an ellipse about which earth is moving and the time period of this motion.