Question

Karl-Pearson’s coefficient of skewness of a distribution is 0.32. Its S.D. is 6.5 and mean 39.6. Then the median of the distribution is given by

• A. 28.61
• B. 38.81C
• C. 29.13
• D. 28.31

Answer 1

Answer: (B)

38.81C

Answer 2

We know that $S_{k} = \frac{M - M_{o}}{\sigma}$, Where M = Mean, $M_{o}$= Mode, σ = S.D.

i.e. $0.32 = \frac{39.6 - M_{o}}{6.5}$ ⇒ $M_{o} = 37.52$ and also know that, $M_{o} =$3median – 2mean

$37.52 =$ 3(Median) – 2(39.6)

Median = 38.81 (approx.)