Question

Karl Pearson's coefficient of rank correlation between the ranks obtained by ten students in Mathematics and Chemistry in a class test as given below is

Rank in Mathematics	1	2	3	4	5	6	7	8	9	10
Rank in Chemistry :	3	10	5	1	2	9	4	8	7	6

• A. 0.224
• B. 0.204
• C. 0.240
• D. None of these

Answer 1

Answer: (A)

0.224

Answer 2

Since $\Sigma d^{2} = 128$

Hence, $\rho = 1 - \frac{6(128)}{10(100 - 1)} = 0.224$.