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Question: Karl Pearson's coefficient of correlation between x and y for the following data is | | | ...

Karl Pearson's coefficient of correlation between x and y for the following data is

x :3489621
y :5377692
A

0.480

B

– 0.480

C

0.408

D

– 0.408

Answer

0.408

Explanation

Solution

xYxyx2y2
35150925
43121609
87566449
97638149
66363636
29180481
12020104
Σx = 33Σy2=253\Sigma y ^ { 2 } = 253

Now, r=ΣxyΣxΣyn{Σx2(Σx)2n}{Σy2(Σy)2n}r = \frac { \Sigma x y - \frac { \Sigma x \cdot \Sigma y } { n } } { \sqrt { \left\{ \Sigma x ^ { 2 } - \frac { ( \Sigma x ) ^ { 2 } } { n } \right\} \left\{ \Sigma y ^ { 2 } - \frac { ( \Sigma y ) ^ { 2 } } { n } \right\} } }

r=0.408r = 0.408.