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Question: Karl Pearson's coefficient of correlation between the heights (in inches) of teachers and students c...

Karl Pearson's coefficient of correlation between the heights (in inches) of teachers and students corresponding to the given data is

Height of teachers x :6667686970
Height of students y :6866697270
A

12\frac { 1 } { \sqrt { 2 } }

B

2\sqrt { 2 }

C

12- \frac { 1 } { \sqrt { 2 } }

D

0

Answer

12\frac { 1 } { \sqrt { 2 } }

Explanation

Solution

Here Σ(xxˉ)(yyˉ)=10,Σ(xxˉ)2=10\Sigma ( x - \bar { x } ) ( y - \bar { y } ) = 10 , \Sigma ( x - \bar { x } ) ^ { 2 } = 10

and Σ(yyˉ)2=20\Sigma ( y - \bar { y } ) ^ { 2 } = 20

Hence the coefficient of correlation is given by

r=Σ(xxˉ)(yyˉ)Σ(xxˉ)2Σ(yyˉ)2=1010×20=10102=12r = \frac { \Sigma ( x - \bar { x } ) ( y - \bar { y } ) } { \sqrt { \Sigma ( x - \bar { x } ) ^ { 2 } \Sigma ( y - \bar { y } ) ^ { 2 } } } = \frac { 10 } { \sqrt { 10 \times 20 } } = \frac { 10 } { 10 \sqrt { 2 } } = \frac { 1 } { \sqrt { 2 } } .