Question

Ka for the acid HA is 1 × 10–6. The value of K for the reaction A– + H3O+$\rightleftharpoons$ HA + H2O is

• A. 1 × 10–6
• B. 1 × 1012
• C. 1 × 10–12
• D. 1 × 106

Answer 1

Answer: (D)

1 × 106

Answer 2

Ka = 10–6 for HA + H2O $\rightleftharpoons$ H3O+ + A– Thus K for reverse reaction is $\frac{1}{10^{- 6}}$= 106