Question

Ka for butyric acid (C3H7COOH) is 2 × 10–5. The pH of 0.2 M solution of butyric acid is ______× 10–1. (Nearest integer) (Given log2 = 0.30)

Answer 1

Ka of butyric acid

⇒2×10-5 PKa
=4.7 pH of 0.2M

solution pH=$\frac{1}{2}$pKa-$\frac{1}{2}$ log C $\frac{1}{2}$ 4.7$\frac{1}{2}$ log0.2

=2.35+0.35

=2.7pH

=27×10-1