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Question

Chemistry Question on Ionic Equilibrium In Solution

Ka1,Ka2Ka _1, Ka _2 and Ka3Ka _3 are the respective ionization constants for the following reactions (a), (b) and (c)
(a) H2C2O4H++HC2O4H _2 C _2 O _4 \rightleftharpoons H ^{+}+ HC _2 O _4^{-}
(b) HC2O4H++HC2O42HC _2 O _4^{-} \rightleftharpoons H ^{+}+ HC _2 O _4^{2-}
(c) H2C2O42H++C2O42H _2 C _2 O _4 \rightleftharpoons 2 H ^{+}+ C _2 O _4^{2-}
The relationship between Ka1,Ka2K _{ a _1}, K _{ a _2} and Ka3K _{ a _3} is given as

A

Ka3=Ka1+Ka2K _{ a _3}= K _{ a _1}+ K _{ a _2}

B

Ka3=Ka1Ka2K _{ a _3}= K _{ a _1}- K _{ a _2}

C

Ka3=Ka1/Ka2K _{ a _3}= K _{ a _1} / K _{ a _2}

D

Ka3=Ka1×Ka2K _{ a _3}= K _{ a _1} \times K _{ a _2}

Answer

Ka3=Ka1×Ka2K _{ a _3}= K _{ a _1} \times K _{ a _2}

Explanation

Solution

H2​C2​O4​⇌H++HC2​O4−​Ka1​​
H2​C2​O4−​⇌H++C2​O42−​Ka2​​
H2​C2​O4​⇌2H++C2​O42−​Ka3​​=Ka1​​×Ka2​​