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Question: \(K_{p} = K_{c}(RT)^{2}\) ⇌ \(H_{2}(g) + I_{2}(g)\) In the above reaction, one mole of each of aceti...

Kp=Kc(RT)2K_{p} = K_{c}(RT)^{2} ⇌ H2(g)+I2(g)H_{2}(g) + I_{2}(g) In the above reaction, one mole of each of acetic acid and alcohol are heated in the presence of little conc. 2HI(g)2HI(g). On equilibrium being attained.

A

1 mole of ethyl acetate is formed

B

2 mole of ethyl acetate are formed

C

1/2 moles of ethyl acetate is formed

D

2/3 moles of ethyl acetate is formed

Answer

2/3 moles of ethyl acetate is formed

Explanation

Solution

In presence of little PCl5,0.20PCl_{5},0.20 (as catalyst) about 2/3 mole of each of PCl3PCl_{3} and Cl2Cl_{2} react to form 2/3 mole of the product at equilibrium.