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Question

Chemistry Question on Equilibrium

Kp/KcK_{p} / K_{c} for the reaction A(g)+2B2(g)AB2(g)A(g)+2 B_{2}(g) \rightleftharpoons A B_{2}(g) is

A

RTRT

B

(RT)2(RT)^{2}

C

1RT\frac{1}{RT}

D

1(RT)2 \frac{1}{(RT)^{2}}

Answer

1(RT)2 \frac{1}{(RT)^{2}}

Explanation

Solution

A(g)+2B(g)AB2(g)A(g)+2B(g)\xrightarrow{{}}A{{B}_{2}}(g)
Kp=KC(RT)Δng{{K}_{p}}={{K}_{C}}{{(RT)}^{\Delta n}}_{g}
Δng=\Delta {{n}_{g}}= change in number of moles = moles of product - moles of reactant =13=2=1-3=-2
\therefore Kp=Kc(RT)2{{K}_{p}}={{K}_{c}}{{(RT)}^{-2}}
\Rightarrow KpKC=1(RT)2\frac{{{K}_{p}}}{{{K}_{C}}}=\frac{1}{{{(RT)}^{2}}}