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Question

Physics Question on Dimensional Analysis

Joule second is the unit of:

A

momentum

B

angular momentum

C

work

D

pressure

Answer

angular momentum

Explanation

Solution

Angular momentum =mυr=m\upsilon r = kilogram !!×!! metresecond !!×!! metre\text{= kilogram }\\!\\!\times\\!\\!\text{ }\frac{\text{metre}}{\text{second}}\text{ }\\!\\!\times\\!\\!\text{ metre} = kilogram !!×!! (metre)2 !!×!! secondsecond !!×!! second\text{= kilogram }\\!\\!\times\\!\\!\text{ }\frac{{{\text{(metre)}}^{\text{2}}}\text{ }\\!\\!\times\\!\\!\text{ second}}{\text{second }\\!\\!\times\\!\\!\text{ second}} =(kg×metresec2)×sec=\left( kg\times \frac{metre}{{{\sec }^{2}}} \right)\times \sec =joule×sec=joule\times \sec