Question

Joule second is the unit of

• A. momentum
• B. angular momentum
• C. work
• D. pressure

Answer 1

Answer: (B)

angular momentum

Answer 2

Angular momentum = mvr = $kilogram \times \frac{ metre }{ second } \times metre$ = $kilogram \times \frac{ ( metre )^2 \times second }{ second \times second }$ = $\Bigg ( kg \times \frac{ ( metre )^2 }{ second^2 } \Bigg ) \times sec$ = $joule \times second$