Question

IUPAC name of $CH{F_2}CBrClF$ ?

Answer 1

Alkenes are saturated hydrocarbons containing only carbon and hydrogen atoms bonded through single bonds. Due to the inertness of alkenes, they only undergo substitution reactions in which hydrogen atoms can be replaced by halogen atoms like fluorine, chlorine, and bromine.

Complete Step By Step Answer:
Chemical compounds are classified into different types based on the functional groups. Hydrocarbons are the chemical compounds consisting of only carbon and hydrogen atoms. Alkanes are the hydrocarbons that consist of carbon and hydrogen atoms bonded through single covalent bonds.
The general molecular formula of alkanes is ${C_n}{H_{2n + 2}}$ where n is the number of carbon atoms. In the given molecule $CH{F_2}CBrClF$ the halogens were replaced in place of hydrogen atoms; the given molecule is the derivative of ethane.
There were three fluorine, one chlorine and one bromine atoms. Two fluorine atoms were substituted on one carbon, and chlorine, bromine and fluorine atoms were substituted on another carbon.
The substituents will get only the $1$ and $2$ numbering as there were only two carbon atoms. Thus, the halogens must be written in alphabetical order, the bromine will have to be written followed by chlorine and fluorine.
The IUPAC name of $CH{F_2}CBrClF$ is $1$ -bromo $1$ -chloro $1,2,2$ -tri fluoroethane.

Note:
While writing the IUPAC nomenclature of chemical compounds the IUPAC rules must have to be followed. The suffix for the alkane is -ane. The numbering of positions of substituents must get a lower number, and the substituents must be written in alphabetical order only. So, in the given molecule bromine was written followed by chlorine and fluorine.