Question

It takes $770\;joules$ energy to raise the temperature of $50.0g$ of mercury by ${110^0}C$ . What is the specific heat of mercury?

Answer 1

When a certain amount of energy is supplied to a metal or any substance the temperature will rise. Given that a mercury metal absorbs $770joules$ energy to raise the temperature of $50.0g$ of mercury by ${110^0}C$ . by substituting these values in the below formula, the specific heat will be determined.
$q = mC\Delta T$
$q$ is energy in joules that was absorbed by a mercury metal
$m$ is mass of mercury metal
$C$ is specific heat of mercury
$\Delta T$ is a change in temperature.

Complete Step By Step Answer:
Mercury is a non-metal that exists in a liquid state in the periodic table. It was represented by the chemical symbol of $Hg$ as mercury has the chemical name of hydrargyrum. So, the chemical name and common name of mercury are different.
The specific heat is defined as the amount of heat required to raise the temperature of a unit mass of substance through one degree centigrade. Specific heat was represented by C.
Given that mercury metal takes $770joules$ energy to raise the temperature of $50.0g$ of mercury by ${110^0}C$ , substitute the above values in the formula.
$C = \dfrac{{770}}{{50 \times 110}} = 0.14J.{C^{ - 1}}.{g^{ - 1}}$
Thus, the specific heat of a mercury is $0.14J.{C^{ - 1}}.{g^{ - 1}}$ .

Note:
Given that the temperature was raised by ${110^0}C$ , it means the change in temperature which was represented by $\Delta T$ is ${110^0}C$ the initial and final temperature were not given but the change in temperature was directly given in Celsius, if we have to express the specific heat in kelvins, it should be converted into kelvins.