Question

It requires 40 ml of 0.5 (M) Ce⁴⁺ to titrate 10 ml of 1 (M) Sn²⁺ where by Sn²⁺ is oxidised to Sn⁴⁺. What is the oxidation state of cerium in the reduction product ?

• A.
  • 3
• B.
  • 2
• C.
  • 1
• D. Zero

Answer 1

Answer: (A)

• 3

Answer 2

Moles of Ce⁴⁺ reacted = 20 × 10^–3 moles

2 moles of Ce⁴⁺ reacts with ( 4– x) moles of Sn²⁺

\ 20 × 10^–3 moles of Ce⁴⁺ reacts with

( 4– x) × 10^–2 moles of Sn²⁺

\ (4 – x) × 10^–2 = 10 × 10^–3

\ 4 – x = 1

or x = + 3.