Question
Question: It is found that when waves of same intensity from two coherent sources superpose at a certain point...
It is found that when waves of same intensity from two coherent sources superpose at a certain point, then the resultant intensity is equal to intensity one wave only.This means that the phase difference between two waves at that point is
A. Zero
B. 3π
C. 32π
D. π
Solution
Coherent sources are that source of light which travels with constant phase difference along with it they have the same frequency. When these sources superpose on each other either forms a constructive or destructive interference depending on their phase difference.
Formula used:
The amplitude of resultant wave is given 3π by:
A=(A12+A22+2A1A2cosθ)21
where A1 and A2 are amplitudes of waves.
Complete step by step answer:
The intensity of the resultant wave varies with amplitude of resultant wave as proportionally to square of amplitude. Intensity of resultant wave is defined as: I=I1+I2+2I1I2cosδ (where δ=λ2π(Δx))
δ is the phase difference and Δx is the path difference between waves.
As given in the question the intensity of the waves are equal then I1=I2 =I0.Substitute the value in the equation of intensity.
I=I0+I0+2I02cosδ
⇒I=4I0cos22δ
Now it is given the resultant intensity is equal to the intensity of one wave only then I=I0, substituted in the above equation.
I0=4I0cos22δ
Solve the equation
\dfrac{1}{4} = {\cos ^2}\dfrac{\delta }{2} \\\
\Rightarrow \dfrac{1}{2} = \cos \dfrac{\delta }{2} \\\
⇒cos3π=cos2δ
∴δ=32π
The phase difference between the waves is 32π.
Hence, option C is the correct answer.
Note: When we calculate the average of the resultant intensity of two waves we find that it is equal to the sum of the given intensities which tell us that the interference of waves also follows the law of conservation of energies. As light is also a form of energy ‘ It can never be created and destroyed by its own’.