Question

It is found that $| \overrightarrow { \mathrm { A } } + \overrightarrow { \mathrm { B } } | = | \overrightarrow { \mathrm { A } } |$. This necessarily implies

• A. $\overrightarrow { \mathrm { B } } = 0$
• B. $\overrightarrow { \mathrm { A } } , \overrightarrow { \mathrm { B } }$ are antiparallel
• C. are perpendicular
• D.

Answer 1

Answer: (B)

$\overrightarrow { \mathrm { A } } , \overrightarrow { \mathrm { B } }$ are antiparallel

Answer 2

If $| \overrightarrow { \mathrm { A } } + \overrightarrow { \mathrm { B } } | = | \overrightarrow { \mathrm { A } } |$ , then either $\vec { B }$ = 0 or . Both are satisfied when and $\vec { B }$ are anti – parallel.