Question

It is because of inability of ns2 electrons of the valence shell to participate in bonding that

• A. $Sn^{2+}$ is reducing while $Pb^{4+}$ is oxidising
• B. $Sn^{2+}$ is oxidising while $Pb^{4+}$ is reducing
• C. $Sn^{2+}$ and $Pb^{2+}$ are both oxidising and reducing
• D. $Sn^{4+}$ is reducing while $Pb^{4+}$ is oxidising

Answer 1

Answer: (A)

$Sn^{2+}$ is reducing while $Pb^{4+}$ is oxidising

Answer 2

The correct option is ($Sn^{2+}$ is reducing while $Pb^{4+}$ is oxidising): .