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Question: It 2 moles of an ideal monoatomic gas at temperature T<sub>0</sub>is mixed with 4 moles of another i...

It 2 moles of an ideal monoatomic gas at temperature T0is mixed with 4 moles of another ideal monoatomic gas at temperature 2T0, then the temperature of the mixture is:

A

53T0\frac{5}{3}T_{0}

B

32T0\frac{3}{2}T_{0}

C

43T0\frac{4}{3}T_{0}

D

54T0\frac{5}{4}T_{0}

Answer

53T0\frac{5}{3}T_{0}

Explanation

Solution

2 × 32\frac{3}{2}RT0 + 4 ×32\frac{3}{2}R(2T0) = 6 × 32\frac{3}{2}RT

302RT0=182RT\frac{30}{2}RT_{0} = \frac{18}{2}RT

T = 159T0=53T0\frac{15}{9}T_{0} = \frac{5}{3}T_{0}