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Question: i<sup>2</sup> + i<sup>4</sup> + i<sup>6</sup> ……… (2n + 1) terms is equal to...

i2 + i4 + i6 ……… (2n + 1) terms is equal to

A

I

B

– I

C

– 1

D

i

Answer

– 1

Explanation

Solution

Sol. Sum = i2 [1 – (i2)2n+1/1–i2]

= –1/2[1–(–1)2n + 1] (Q(–1)odd = –1)= –1/2 [2] Ž – 1