Question
Question: I<sub>1</sub> = \(\int_{0}^{\pi/2}{\sin xdx},\) I<sub>2</sub> = \(\int_{0}^{\pi/2}{\sin^{3}xdx}\), t...
I1 = ∫0π/2sinxdx, I2 = ∫0π/2sin3xdx, then -
A
I1> I2
B
I1< I2
C
I1 = I2
D
I2 = 0
Answer
I1> I2
Explanation
Solution
Q 0 < x < p/2 Ž sin x > sin3x
Ž ∫0π/2sinxdx>∫0π/2sin3xdx Ž I1 > I2