Question

Is there any change in the hybridisation of B and N atoms as a result of the following reaction?
$BF_3+ NH_3 \rightarrow F_3B.NH_3$

Answer 1

Boron atom in $BF_3$ is $sp ^2$ hybridized. The orbital picture of boron in the excited state can be shown as:

Nitrogen atom in $NH_3$ is $sp ^3$ hybridized. The orbital picture of nitrogen can be represented as:

After the reaction has occurred, an adduct $F_3B$, $NH_3$ is formed as hybridization of $'B'$ changes to $sp^3$ . However, the hybridization of $'N'$ remains intact.