Question

IP values and EA values of elements A, B, C, and D are given in a tabular form. Identify the respective strongest oxidizing agent and reducing agent among them.

| IP Values| EA Values
---|---|---
(A)| 450| 140
(B)| 225| 700
(C)| 300| 400
(D)| 700| 1035

Options-
(A) B, D
(B) B, A
(C) D, A
(D) D, B

Answer 1

Hint Here, IP signifies ionisation potential and EA signifies electron affinity. They are the interrelated concepts with oxidising and the reducing agents; sometimes directly or indirectly proportional.

Complete step by step solution:
Let us define the terms given and discuss the relationship between them;
Electron affinity-
It is the amount of energy released when an electron is added to a neutral atom or a molecule in the gaseous state to result in the formation of a negative ion.
Ionisation potential-
It is the amount of energy required to remove an electron from an isolated atom or a molecule.
Oxidising agent- An atom or a molecule which gains electrons and gets reduced to oxidise another species of atoms or molecules.
Reducing agent- An atom or a molecule which loses electrons and gets oxidised to reduce another species of atoms or molecules.
The relationships- $EA\propto \operatorname{Re}duction$ and $IP\propto \dfrac{1}{Oxidation}$
Thus,
D – IP: 700 and EA: 1035 (strongest oxidising agent)
B – IP: 225 and EA: 700 (strongest reducing agent)

Hence, option (D) is correct.

Note: In general, More the electron affinity, stronger will be the oxidising agent. Less the ionisation potential, stronger will be the reducing agent.