Question

Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr's theory, the spectral lines emitted by hydrogen will be –

• A. One
• B. Two
• C. Three
• D. Four

Answer 1

Answer: (C)

Three

Answer 2

Due to 12.1 eV energy it is excited to 3^rd orbit, so total lines

= $\frac{n(n–1)}{2}$

= $\frac{3 \times 2}{2}$ = 3 lines