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Chemistry Question on Classification of elements & periodicity in properties

Ionization potential and electron affinity of fluorine are 17.42 and 3.45 eV atom−1atom^{-1} respectively. Electronegativity of fluorine will be approximately

A

3

B

6

C

4

D

2

Answer

4

Explanation

Solution

Electronegativity=0.374[IE+EA]2+0.17=0.374 \frac{\left[IE+EA\right]}{2}+0.17 =0.374[17.42+3.45]2+0.17=4.07≈4=0.374 \frac{\left[17.42+3.45\right]}{2}+0.17=4.07 \approx4