Solveeit Logo
Login

Question

Question: Ionization energy of hydrogen is 13.6 eV. If \(h = 6.6 \times 10^{- 34}J -\)sec, the value of R wil...

Ionization energy of hydrogen is 13.6 eV. If

h=6.6×10−34J−h = 6.6 \times 10^{- 34}J -sec, the value of R will be of the order of.

A

1010m−110^{10}m^{- 1}

B

107m−110^{7}m^{- 1}

C

104m−110^{4}m^{- 1}

D

10−7m−110^{- 7}m^{- 1}

Answer

107m−110^{7}m^{- 1}

Explanation

Solution

E=−RchE = - Rch ⇒ R=−Ech=−13.6×1.6×10−193×108×6.6×10−34R = - \frac{E}{ch} = - \frac{13.6 \times 1.6 \times 10^{- 19}}{3 \times 10^{8} \times 6.6 \times 10^{- 34}}

=1.098×107perm= 1.098 \times 10^{7}perm