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Question: Intermolecular forces between n- hexane and n- heptanes are nearly same as between hexane and heptan...

Intermolecular forces between n- hexane and n- heptanes are nearly same as between hexane and heptanes individually, When these two are mixed, which of the following is not true about the solution formed?

A

It obeys Raoult’s law, i.e. PA=xApAo\mathrm { P } _ { \mathrm { A } } = \mathrm { x } _ { \mathrm { A } } \mathrm { p } _ { \mathrm { A } } ^ { \mathrm { o } } and PB=xBpBo\mathrm { P } _ { \mathrm { B } } = \mathrm { x } _ { \mathrm { B } } \mathrm { p } _ { \mathrm { B } } ^ { \mathrm { o } }

B

ΔHmixing \Delta H _ { \text {mixing } } is zero

C

ΔVmixing \Delta V _ { \text {mixing } } is zero

D

It forms minimum boiling azeotrope.

Answer

It forms minimum boiling azeotrope.

Explanation

Solution

Azeotropes are formed by the solutions which show deviations from ideal behavior.