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Question

Physics Question on electrostatic potential and capacitance

Intensity of an electric field EE due to a dipole, depends on distance rr as:

A

E∝1r4E\propto \frac{1}{r^{4}}

B

E∝1r3 E\propto \frac{1}{r^{3}}

C

E∝1r2 E\propto \frac{1}{r^{2}}

D

E∝1rE\propto \frac{1}{r}

Answer

E∝1r3 E\propto \frac{1}{r^{3}}

Explanation

Solution

Here: Electric field =E=E Distance =r=r The electric field intensity due to dipole is E=14πε0×2pr3∝1r3E=\frac{1}{4 \pi \varepsilon_{0}} \times \frac{2 p}{r^{3}} \propto \frac{1}{r^{3}}