Question

integration of sin2x

Answer 1

$-\frac{1}{2}\cos(2x) + C$

Answer 2

To find the integral of $\sin(2x)$, we use the standard integration formula for trigonometric functions. The general formula for the integral of $\sin(ax)$ is:

$\int \sin(ax) \, dx = -\frac{1}{a}\cos(ax) + C$

In this case, $a = 2$. Applying the formula:

$\int \sin(2x) \, dx = -\frac{1}{2}\cos(2x) + C$

where $C$ is the constant of integration.

The integral of $\sin(2x)$ is found by applying the standard integration formula $\int \sin(ax) \, dx = -\frac{1}{a}\cos(ax) + C$. Here, $a=2$, leading to $-\frac{1}{2}\cos(2x) + C$.