Question
Mathematics Question on integral
Integrate the function: xsin 3x
Answer
Let I=∫xsin 3xdx
Taking x as first function and sin 3x as second function and integrating by parts, we obtain
I=x∫sin 3xdx−∫(dxdx)∫sin 3xdx
I=x(3−cos 3x)−∫1.(3−cos 3x)dx
I=3−xcos 3x+31∫cos 3xdx
I=3−xcos 3x+91sin 3x+C