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Question

Mathematics Question on integral

Integrate the function: xsin xx sin \ x

Answer

Let\ I=$$∫x sin\ x dx

Taking x as first function and sin xsin \ x as second function and integrating by parts, we obtain

I=I = xsin xdx[(ddxx)sin xdx]dxx∫sin\ x dx-∫[{(\frac {d}{dx} x)∫sin\ x dx}]dx

I =$$x(-cosx)-∫1.(-cosx)dx

I=xcos x+sin x+CI =-xcos\ x+sin\ x+C