Question

Integrate the function: $\frac{x}{9-4x^2}$

Answer 1

Let 9-4x2 = t

∴ -8x dx = dt

$\Rightarrow\int \frac{x}{9-4x^2}dx = \frac{-1}{8}\int\frac{1}{t}dt$

= $\frac{-1}{8}$log|t| +C

= $\frac{-1}{8}$log|9-4x2| +C