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Question

Mathematics Question on integral

Integrate the function: (logx)2x\frac{(\log x)^2}{x}

Answer

Let log |x| = t

1x\frac{1}{x}dx = dt

(logx)2xdx=t2dt\Rightarrow \int \frac{(\log\mid x\mid)^2}{x}dx=\int t^2dt
=t33+C\frac{t^3}{3}+C

=(logx)33+C\frac{(\log \mid x\mid )^3}{3}+C