Question
Mathematics Question on integral
Integrate the function: e3logx−e2logxe5logx−e4logx
Answer
e3logx−e2logxe5logx−e4logx=e2logx(elogx−1)e4logx(elogx−1)
=e2logx
=elogx2
=x2
∴∫\frac{e^{5log\,x-e^{4\,logx}}}{e^{3\,logx}-e^{2\,logx}}$$=\int x^2dx=\frac{x^3}{3}+C