Question
Mathematics Question on integral
Integrate the function: 1+x22x
Answer
Let 1+x2 = t
∴ 2x dx = dt
⇒∫1+x22xdx=∫dt1
= log |t| +C
= log |1+x2| +C
= log (1+x2) +C
Integrate the function: 1+x22x
Let 1+x2 = t
∴ 2x dx = dt
⇒∫1+x22xdx=∫dt1
= log |t| +C
= log |1+x2| +C
= log (1+x2) +C