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Question

Question: \(\int_{}^{}x^{x}\) . (1 + logx) dx =...

xx\int_{}^{}x^{x} . (1 + logx) dx =

A

xx

B

x2x

C

xxlogx

D

12\frac{1}{2} (1 + log x)2

Answer

xx

Explanation

Solution

Put xx = t

xx(1+ logx) dx = dt ̃ \dt\int_{}^{}{dt} = t + c = xx + c