Question
Question: \(\int_{}^{}x^{x}\) . (1 + logx) dx =...
∫xx . (1 + logx) dx =
A
xx
B
x2x
C
xxlogx
D
21 (1 + log x)2
Answer
xx
Explanation
Solution
Put xx = t
xx(1+ logx) dx = dt ̃ \∫dt = t + c = xx + c
∫xx . (1 + logx) dx =
xx
x2x
xxlogx
21 (1 + log x)2
xx
Put xx = t
xx(1+ logx) dx = dt ̃ \∫dt = t + c = xx + c