\[\integral\_{}^{}{x^{2}(3)^{x^{3} + 1}dx =}] | MATH - INTEGRATION BY SUBSTITUTION | SolveeIt

$\int_{}^{}{x^{2}(3)^{x^{3} + 1}dx =}$

$(3)^{x^{3}} + c$

$\frac{(3)^{x^{3}}}{\log 3} + c$

$\log 3(3)^{x^{3}} + c$

$\int_{}^{}{\sec^{2/3}x\text{cose}\text{c}^{4/3}x\mspace{6mu} dx =}$

Answer

$\frac{(3)^{x^{3}}}{\log 3} + c$

Explanation

$x + 4\log(1 - x) + c$

$x + 4\log(x - 1) + c$ .

Question: \[\int_{}^{}{x^{2}(3)^{x^{3} + 1}dx =}\]...