\[\integral\_{}^{}{\tan^{4}x\mspace{6mu} dx =}] | MATH - FUNDAMENTAL INTEGRATION | SolveeIt

$\int_{}^{}{\tan^{4}x\mspace{6mu} dx =}$

$\tan^{3}x - \tan x + x + c$

$\frac{1}{3}\tan^{3}x - \tan x + x + c$

$\frac{1}{3}\tan^{3}x + \tan x + x + c$

$\frac{1}{3}\tan^{3}x + \tan x + 2x + c$

Answer

$\tan^{3}x - \tan x + x + c$

Explanation

$\sin\sqrt{x} + c$

$\frac{1}{2}\cos\sqrt{x} + c$

$\int_{}^{}{\frac{x + 1}{\sqrt{1 + x^{2}}}dx} =$

Question: \[\int_{}^{}{\tan^{4}x\mspace{6mu} dx =}\]...