Question
Question: \[\int_{}^{}{(\sec x + \tan x)^{2}dx =}\]...
∫(secx+tanx)2dx=
A
2(secx+tanx)−x+c
B
1/3(secx+tanx)3+c
C
secx(secx+tanx)+c
D
2(secx+tanx)+c
Answer
1/3(secx+tanx)3+c
Explanation
Solution
−e2x+11 (formula).
∫(secx+tanx)2dx=
2(secx+tanx)−x+c
1/3(secx+tanx)3+c
secx(secx+tanx)+c
2(secx+tanx)+c
1/3(secx+tanx)3+c
−e2x+11 (formula).