(\integral\_{}^{}\frac{x^{4}–x^{2} + 1}{x^{2}–x + 1}) dx = | MATH - INTEGRATION BY SUBSTITUTION | SolveeIt

$\int_{}^{}\frac{x^{4}–x^{2} + 1}{x^{2}–x + 1}$ dx =

$\frac{1}{3}x^{3} + \frac{1}{2}x^{2} + x + c$

$\frac{1}{3}x^{3}–\frac{1}{2}x^{2} + x + c$

$\frac{1}{3}x^{3} + \frac{1}{2}x^{2}–x + c$

None of these

Answer

$\frac{1}{3}x^{3} + \frac{1}{2}x^{2} + x + c$

Explanation

$\int \frac { x ^ { 4 } + x ^ { 2 } + 1 } { x ^ { 2 } - x + 1 }$ dx

= $\frac { x ^ { 3 } } { 3 } + \frac { x ^ { 2 } } { 2 } + x + c$

Question: \(\int_{}^{}\frac{x^{4}–x^{2} + 1}{x^{2}–x + 1}\) dx =...