Question

$\int_{}^{}{\frac{dx}{\sqrt{1 + x} + \sqrt{x}} =}$is equal to.

• A. $\frac{2}{3}(1 + x)^{2/3} - \frac{2}{3}x^{2/3} + c$
• B. $\frac{3}{2}(1 + x)^{2/3} + \frac{3}{2}x^{2/3} + c$
• C. $\frac{3}{2}(1 + x)^{3/2} + \frac{3}{2}x^{3/2} + c$
• D. $\frac{2}{3}(1 + x)^{3/2} - \frac{2}{3}x^{3/2} + c$

Answer 1

Answer: (D)

$\frac{2}{3}(1 + x)^{3/2} - \frac{2}{3}x^{3/2} + c$

Answer 2

$1 + \tan x = t$

$2 + \tan x = t$

$\tan x = t$.