\[\integral\_{}^{}{\frac{dx}{e^{- 2x}(e^{2x} + 1)^{2}} =}] | MATH - FUNDAMENTAL INTEGRATION | SolveeIt | Solveeit

Today, August 18

Question

$\int_{}^{}{\frac{dx}{e^{- 2x}(e^{2x} + 1)^{2}} =}$

A

$\frac{- 1}{2(e^{2x} + 1)} + c$

B

$\frac{1}{2(e^{2x} + 1)} + c$

C

$\frac{1}{e^{2x} + 1} + c$

D

$\frac{- 1}{e^{2x} + 1} + c$

Answer

$\frac{1}{e^{2x} + 1} + c$

Explanation

Solution

$2\cos\sqrt{x} + c$

$2\sin\sqrt{x} + c$