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Question: \(\int_{}^{}\frac{dx}{4\cos^{3}2x–3\cos 2x}\) =...

∫dx4cos⁡32x–3cos⁡2x\int_{}^{}\frac{dx}{4\cos^{3}2x–3\cos 2x} =

A

13\frac{1}{3}log[sec6x + tan6x] + c

B

16\frac{1}{6}log[sec6x + tan6x] + c

C

log[sec 6x + tan 6x] + c

D

None of these

Answer

16\frac{1}{6}logsec6x+tan6xsec6x + tan6x + c

Explanation

Solution

= =

= 16\frac { 1 } { 6 }log (sec 6x + tan6x) + c