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Question

Question: \(\int_{}^{}\frac{\cos 2x - \cos 2\alpha}{\cos x - \cos\alpha}dx =\) is equal to....

∫cos⁡2x−cos⁡2αcos⁡x−cos⁡αdx=\int_{}^{}\frac{\cos 2x - \cos 2\alpha}{\cos x - \cos\alpha}dx = is equal to.

A

2[sin⁡x+xcos⁡α]+c2\lbrack\sin x + x\cos\alpha\rbrack + c

B

2[sin⁡x+sin⁡α]+c2\lbrack\sin x + \sin\alpha\rbrack + c

C

2[−sin⁡x+xcos⁡α]+c2\lbrack - \sin x + x\cos\alpha\rbrack + c

D

−2[sin⁡x+sin⁡α]+c- 2\lbrack\sin x + \sin\alpha\rbrack + c

Answer

2[sin⁡x+sin⁡α]+c2\lbrack\sin x + \sin\alpha\rbrack + c

Explanation

Solution

∫cosec2x1+cot⁡xdx=\int_{}^{}{\frac{\text{cose}\text{c}^{2}x}{1 + \cot x}dx =}.