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Question

Question: \(\int_{}^{}\frac{ax^{–2} + bx^{–1} + c}{x^{–3}}dx\) =...

ax2+bx1+cx3dx\int_{}^{}\frac{ax^{–2} + bx^{–1} + c}{x^{–3}}dx =

A

2ax2 + 3bx3 + 4cx4 + k

B

6ax2 + 4bx3 + 3cx4 + k

C

a + b + cx2 + k

D

12\frac{1}{2}ax2 + 13\frac{1}{3}bx3 + 14\frac{1}{4}cx4 + k

Answer

12\frac{1}{2}ax2 + 13\frac{1}{3}bx3 + 14\frac{1}{4}cx4 + k

Explanation

Solution

dx =(ax+bx2+cx3)dx\int \left( a x + b x ^ { 2 } + c x ^ { 3 } \right) d x

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