Question

$\int_{}^{}{\frac{3x^{2}}{x^{6} + 1}dx =}$

• A. $\log(x^{6} + 1) + c$
• B. $\tan^{- 1}(x^{3}) + c$
• C. $3\tan^{- 1}(x^{3}) + c$
• D. None of these

Answer 1

Answer: (A)

$\log(x^{6} + 1) + c$

Answer 2

Put

$a \cos ^ { 2 } x + b \sin ^ { 2 } x = t$ $e^{- x} + c$

Then $- e^{- x} + c$

$\int_{}^{}\frac{\cot x\tan x}{\sec^{2}x - 1}\mspace{6mu} dx =$.