(\integral\_{}^{}{\frac{1}{x}\sec^{2}(\log x)dx =}) | MATH - FUNDAMENTAL INTEGRATION | SolveeIt | Solveeit

Today, August 18

Question

$\int_{}^{}{\frac{1}{x}\sec^{2}(\log x)dx =}$

A

$\tan(\log x) + c$

B

$\log(\sec x) + c$

C

$\log(\tan x) + c$

D

$\sec(\log x)\mspace{6mu}.\mspace{6mu}\tan(\log x) + c$

Answer

$\log(\sec x) + c$

Explanation

Solution

$\frac{1}{\log a}\cos^{- 1}a^{x} + c$ .