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Question: \(\int_{}^{}{e^{x}\lbrack\log(\sec x + \tan x) + \sec x\rbrack}\) dx =...

∫ex[log⁡(sec⁡x+tan⁡x)+sec⁡x]\int_{}^{}{e^{x}\lbrack\log(\sec x + \tan x) + \sec x\rbrack} dx =

A

ex log tan x + c

B

ex log (sec x + tan x) + c

C

ex log sec x + c

D

None of these

Answer

ex log (sec x + tan x) + c

Explanation

Solution

Log (sec x + tan x) = t

sec x dx = dt

\ ex log (sec x + tan x) + c