Question
Question: \(\int_{}^{}e^{–2x}\) sin 3x dx =...
∫e–2x sin 3x dx =
A
131 e–2x [sin 3x + cos 3x ] + c
B
– 131e–2x [sin3x + cos 3x] + c
C
131e–2x [2sin 3x + 3 cos 3x] + c
D
–131e–2x [2sin 3x + 3 cos 3x] + c
Answer
–131e–2x 2sin3x+3cos3x + c
Explanation
Solution
Use formula ∫eax.sin(bx+c)dx
= [a sin(bx + c) – b cos(bx + c)] + c