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Question

Question: \[\int_{}^{}a^{x}da =\]...

∫axda=\int_{}^{}a^{x}da =

A

axlog⁡ea+c\frac{a^{x}}{\log_{e}a} + c

B

ax logea + c

C

ax+1x+1+c\frac{a^{x + 1}}{x + 1} + c

D

xax–1 + c

Answer

ax+1x+1+c\frac{a^{x + 1}}{x + 1} + c

Explanation

Solution

∫axda=ax+1x+1+c\int a ^ { x } d a = \frac { a ^ { x + 1 } } { x + 1 } + c